solve each system. Then drag each one to the column headed by a point which could be its solution. 2x-6y=10 x+8y=5<

Question

solve each system. Then drag each one to the column headed by a point which could be its solution.

2x-6y=10
x+8y=5

3x-y=-5
x+4y=7

2x-2y=12
-2x-3y=-22

x-y=2
2x+y=13

(5,y) (x,2)

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Adalynn 2 weeks 2021-09-13T14:19:26+00:00 1 Answer 0

Answers ( )

    0
    2021-09-13T14:21:00+00:00

    Answer:

    Part 1) The solution of the system of equations is the point (5,0) -> the solution could be (5,y)                  

    Part 2) The solution of the system of equations is the point (-1,2) –> the solution could be (x,2)            

    Part 3) The solution of the system of equations is the point (8,2) -> the solution could be (x,2)            

    Part 4) The solution of the system of equations is the point (5,3) -> the solution could be (5,y)            

    Step-by-step explanation:

    Part 1) we have

    2x-6y=10 —-> equation A

    x+8y=5 —> equation B

    Solve the system by elimination

    Multiply equation B by -2 both sides

    -2(x+8y)=-2(5)

    -2x-16y=-10 —-> equation C

    Adds equation A and equation C

    2x-6y=10\\-2x-16y=-10\\--------\\-6y-16y=10-10\\-22y=0\\y=0

    Find the value of x

    substitute the value of y in any equation

    x+8(0)=5

    x=5

    therefore

    The solution of the system of equations is the point (5,0) -> the solution could be (5,y)

    Part 2) we have

    3x-y=-5 —-> y=3x+5 —-> equation A

    x+4y=7 —> equation B

    Solve the system by substitution

    substitute equation A in equation B

    x+4(3x+5)=7

    solve for x

    x+12x+20=7

    13x=7-20

    13x=-13

    x=-1

    Find the value of y

    y=3(-1)+5=2

    therefore

    The solution of the system of equations is the point (-1,2) –> the solution could be (x,2)

    Part 3) we have

    2x-2y=12 —-> equation A

    -2x-3y=-22 —> equation B

    Solve the system by elimination

    Adds equation A and equation B

    2x-2y=12\\-2x-3y=-22\\--------\\-2y-3y=12-22\\-5y=-10\\y=2

    Find the value of x

    substitute the value of y in any equation

    2x-2(2)=12

    2x-4=12

    2x=12+4

    2x=16

    x=8

    therefore

    The solution of the system of equations is the point (8,2) -> the solution could be (x,2)

    Part 4) we have

    x-y=2 —-> y=x-2 —-> equation A

    2x+y=13 —> equation B

    Solve the system by substitution

    substitute equation A in equation B

    2x+x-2=13

    solve for x

    3x=13+2

    3x=15

    x=5

    Find the value of y

    y=5-2=3

    therefore

    The solution of the system of equations is the point (5,3) -> the solution could be (5,y)

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