solve the equation, 3x^2+5x+2=0 using the quadratic formula

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solve the equation, 3x^2+5x+2=0 using the quadratic formula

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Isabelle 6 days 2021-09-09T14:03:41+00:00 1 Answer 0

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    2021-09-09T14:05:10+00:00

    Given a quadratic equation ax^2+bx+c=0, the two solution (if they exist) are given by the formula

    x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

    In your case, the coefficients are

    a=3,\quad b=5,\quad c=2

    So the quadratic formula becomes

    x_{1,2}=\dfrac{-5\pm\sqrt{25-24}}{6} = \dfrac{-5\pm 1}{6}

    So, the two solutions are

    x_1 = \dfrac{-5+1}{6}=-\dfrac{4}{6}=-\dfrac{2}{3}

    x_2 = \dfrac{-5-1}{6}=-\dfrac{6}{6}=-1

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