Solve the following system of equations. 0.12x – 0.07y = -1.35 0.4x + 0.8y = 4.8

Question

Solve the following system of equations.

0.12x – 0.07y = -1.35

0.4x + 0.8y = 4.8

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Arianna 1 week 2021-10-11T00:00:23+00:00 1 Answer 0

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    2021-10-11T00:01:36+00:00

    Answer:

    x = -6 and y = 9

    Step-by-step explanation:

    It is given that,

    0.12x – 0.07y = -1.35    —–(1)

    0.4x + 0.8y = 4.8   —–(2)

    To find the value of x and y

    eq(1) * 100 ⇒

    12x + 7y = -135   —–(3)

    eq(2) /0.4 ⇒

    x + 2y = 12   —–(4)

    eq(4) * 12 ⇒

    12x + 24y = 144   —(5)

    eq(5) – eq(3) ⇒

    12x + 24y = 144   —(5)

    12x – 7y = -135  —–(3)

     0  + 31y = 279

    y = 279/31 = 9

    Substitute the value of y in eq(4)

    x + 2y = 12   —–(4)

    x + 2*9 = 12

    x = 12 – 18 = -6

    Therefore x = -6 and y = 9

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