Suppose a life insurance policy costs $24 for the first unit of coverage and then $6 for each additional unit of coverage. Let C(x) be the c

Question

Suppose a life insurance policy costs $24 for the first unit of coverage and then $6 for each additional unit of coverage. Let C(x) be the cost for insurance of x units of coverage. What will 10 units of coverage cost?

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5 days 2021-09-15T22:55:06+00:00 2 Answers 0

Answers ( )

  1. Charlotte
    0
    2021-09-15T22:56:07+00:00

    Answer:

    10 Units would cost $78

    Step-by-step explanation:

    We will be using the following equation to solve this problem

    C(x) = 24+6(x-1)

    Where x will be the amount of units of coverage that are sold. The equation subtracts 1 from the amount of units sold (since the first unit costs $24) and multiplies that by $6 which is the cost per unit. Then it adds $24 to that, which gives us the total cost.

    Since we sold 10 units of coverage we plug that into the equation

    C(10) = 24+6(10-1)

    C(10) = 24+6(9)

    C(10) = 24+54

    C(10) = 78

    So 10 units of coverage sold would cost $78

    0
    2021-09-15T22:56:21+00:00

    Answer:

    C(x) =24+6(z-1) where z is the total of units sold.

    Therefore if z=10 units, the answer is: C(x)=24+6(10-1)

    Or 24+6(9)

    Or $78

    Step-by-step explanation:

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