The number N = 100 + 100^2 + 100^3 + … + 100^n . Find the least possible value of n such that the number N is divisible by 11. NEED QUICKL

Question

The number N = 100 + 100^2 + 100^3 + … + 100^n . Find the least possible value of n such that the number N is divisible by 11. NEED QUICKLY! Thanks!!!

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Peyton 2 weeks 2021-09-09T12:15:18+00:00 1 Answer 0

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    2021-09-09T12:16:18+00:00

    Answer:

      n = 11

    Step-by-step explanation:

    100 mod 11 = 1, which is the remainder from division by 11 for each of the terms of the sum. 11 terms of the sum are needed in order to make the remainders add up to a number divisible by 11.

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