The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

Question

The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

What is the constant of the quadratic expression in this equation?

x2 + x + ___ = 0
Help quick please, its timed

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Abigail 1 day 2021-09-15T19:56:33+00:00 1 Answer 0

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    2021-09-15T19:57:56+00:00

    Answer:

    The constant of the quadratic equation is -420

    Step-by-step explanation:

    Let

    x —-> the first consecutive integer (smaller integer)

    x+1 —> the second consecutive integer

    we know that

    x(x+1)=420

    Apply distributive property left side

    x^2+x=420

    subtract 420 both sides

    x^2+x-420=420-420

    x^2+x-420=0

    therefore

    The constant of the quadratic equation is -420

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