the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 48 M. the length of the alley is 5 times

Question

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 48 M. the length of the alley is 5 times the width. find the length and the width of the playing alley​

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Hailey 2 weeks 2021-11-22T00:04:35+00:00 1 Answer 0

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    2021-11-22T00:05:53+00:00

    Answer:

    Length is 20 m and width is 4 m.

    Step-by-step explanation:

    Given:

    Perimeter of the rectangular alley, P=48\textrm{ m}

    Length is 5 times the width.

    Let width be x.

    So, as per question,

    Length,l = 5x

    Now, perimeter of rectangle is given as:

    P=2(l+b)

    Plug in 48 for P, 5x for l and x for b.

    48=2(5x+x)\\48=2(6x)\\48=12x\\x=\frac{48}{12}=4

    Therefore, width is 4 m.

    Length is 5x=5\times 4=20 m.

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