Share

## The sum of 5 55 consecutive integers is 110 What is the fourth number in this sequence

Question

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Question

### Select the correct answer. Ryan opens a bank account with $50. Each month he deposits an amount that doubles his savings. Ryan gets $2 from

### Simplify: -8(7x + 4) + 10(3x) helppppp

### Find the limit. Use l’Hospital’s Rule where appropriate. If there is a more elementary method, consider using it. lim x → (π/2)+ cos(x)

### Suppose mr reeds class has 3 hours for presentations how many projects can be presented show your solution by writing both a division equati

### The graph of function f is defined as the set of all points (x, f(x)), where x is in the domain of f. Please select the be

## Answers ( )

Question:The sum of 5 consecutive integers is 110

. What is the fourth number in this sequence

Answer:The fourth number in this sequence is 23

Step-by-step explanation:Explanation:

Consecutive numbers are numbers that come one after another with no numerical gaps. Like these:

4,

5

,

6

,

7

,

8 or these 17

,

18,

19

,

20

,

21

We need to

find 5 consecutive integers that add up to 110.

Let’s call the first integer in the series

N for number

. The next integer will be

N

+

1 since it is 1 greater than N

.

The next integers will be N+

2

, N

+

3 and N

+

4 since they are 2, 3 and 4 greater than N respectively.

N

+

(

N

+

1

)

+

(

N

+

2

)+(

N

+

3

)

+

(

N

+

4

)

=

110

Now

remove parentheses and add like terms:

N

+

N

+

1

+

N

+

2

+

N

+

3

+

N

+

4

=

110

5N

+

10

=

110

Now finish simplifying:

5

N

+

10=

110

5

N

=

100

N

=

20

Since N

=

20

our 5 consecutive numbers are:

20,

21

,

22

,

23

,

24