To balance a seesaw the distance a person is from the fulcrum is inversely proportional to his or her weight. Roger who weights 120 pounds i

Question

To balance a seesaw the distance a person is from the fulcrum is inversely proportional to his or her weight. Roger who weights 120 pounds is sitting 6 feet from the fulcrum. Ellen weights 108 pounds. How far from the fulcrum must she sit to balance the seesaw? Round to the nearest hundredth of a root

in progress 0
2 days 2021-09-15T04:52:31+00:00 2 Answers 0

Answers ( )

  1. Charlotte
    0
    2021-09-15T04:53:37+00:00

    Answer:

    6.67 ft

    Step-by-step explanation:

       Let d = distance

     and w = weight

    Then d = k/w

     or dw = k

     Let d1 and w1 represent Roger

    and d2 and w2 represent Ellen. Then

    d1w1 = d2w2

    Data:

    d1 = 6 ft; w1  = 120 lb

    d2 = ?    ; w2 = 108 lb

    Calculation:

    6 × 120 = 108d2

           720 = 108d2

             d2 = 720/108 = 6.67 ft

    Ellen must sit 6.67 ft from the fulcrum.

    0
    2021-09-15T04:54:22+00:00

    Answer:

    5.4 feet

    Step-by-step explanation:

    Step 1 : Prepare the data

    Roger’s weight = 120

    Roger’s distance from fulcrum = 6 feet

    Ellen’s weight = 108

    Ellen’s distance from fulcrum = D

    Step 2 : Make an equation to find the unknown

    Inverse proportion means that you have to cross multiply.

               Weight                              Distance

                  120                                     6

                  108                                     D

    120 x D = 108 x 6

    Step 3 : Solve the equation to find the unknown

    120 x D = 108 x 6

    D = 108 x 6

            120

    D = 5.4 feet

    Ellen must sit 5.4 feet far from the fulcrum to balance the seesaw.

    !!

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )