## To balance a seesaw the distance a person is from the fulcrum is inversely proportional to his or her weight. Roger who weights 120 pounds i

Question

To balance a seesaw the distance a person is from the fulcrum is inversely proportional to his or her weight. Roger who weights 120 pounds is sitting 6 feet from the fulcrum. Ellen weights 108 pounds. How far from the fulcrum must she sit to balance the seesaw? Round to the nearest hundredth of a root

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2 days 2021-09-15T04:52:31+00:00 2 Answers 0

1. 6.67 ft

Step-by-step explanation:

Let d = distance

and w = weight

Then d = k/w

or dw = k

Let d1 and w1 represent Roger

and d2 and w2 represent Ellen. Then

d1w1 = d2w2

Data:

d1 = 6 ft; w1  = 120 lb

d2 = ?    ; w2 = 108 lb

Calculation:

6 × 120 = 108d2

720 = 108d2

d2 = 720/108 = 6.67 ft

Ellen must sit 6.67 ft from the fulcrum.

5.4 feet

Step-by-step explanation:

Step 1 : Prepare the data

Roger’s weight = 120

Roger’s distance from fulcrum = 6 feet

Ellen’s weight = 108

Ellen’s distance from fulcrum = D

Step 2 : Make an equation to find the unknown

Inverse proportion means that you have to cross multiply.

Weight                              Distance

120                                     6

108                                     D

120 x D = 108 x 6

Step 3 : Solve the equation to find the unknown

120 x D = 108 x 6

D = 108 x 6

120

D = 5.4 feet

Ellen must sit 5.4 feet far from the fulcrum to balance the seesaw.

!!