Use the information provided to write the equation of the parabola in vertex form. y=-3×2 – 6x +1 A D=3(x+3)²+2 B. y = 3(x

Question

Use the information provided to write the equation of the parabola in vertex form.
y=-3×2 – 6x +1
A D=3(x+3)²+2
B. y = 3(x+1)+4
y=-3(x+3)² +2
D. y=-3(x+1)+4
Please help

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Genesis 6 days 2021-10-11T21:16:36+00:00 1 Answer 0

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    2021-10-11T21:18:21+00:00

    Answer: y=-3(x+1)^2+4

    Step-by-step explanation:

    The vertex form of the equation of  a parabola is:

     f(x) = a(x - h)^2 + k

    Where (h, k) is the vertex of the parabola.

    To write y=-3x^2 - 6x +1 in vertex form, you need to complete the square:

    1. Move the 1 to the other side of the equation:

    y-1=-3x^2 - 6x

    2. Since the leading coefficient must be 1, you need to factor out -3:

    y-1=-3(x^2 + 2x)

    3. Divide the coefficient of the x-term inside the parentheses by 2 and square it:

      (\frac{2}{2})^2=1

    4. Now add 1 inside the parethenses and -3(1) to the other side of the equation (because you factored out -3):

    y-1-3(1)=-3(x^2 + 2x+1)

    y-4=-3(x^2 + 2x+1)

    5. Convert the right side of the equation to a squared expression:

     y-4=-3(x+1)^2

    6. And finally, you must solve for “y”:

    y=-3(x+1)^2+4

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