What are the x- and y-intercepts for the equation “2x + 3y = 6”? (2,0) & (3,0) (0, 2) & (3, 0) (0,3) & (2,0)

Question

What are the x- and y-intercepts for the equation “2x + 3y = 6”?
(2,0) & (3,0)
(0, 2) & (3, 0)
(0,3) & (2,0)
(0,3) & (0,2)​

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2 weeks 2021-10-12T09:31:46+00:00 2 Answers 0

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    0
    2021-10-12T09:32:47+00:00

    2x+3y=6
    The answer is
    (0,2) & (3,0)
    You have to put 0 in the x then solve for y
    After u get y replace the number in y and solve for x

    0
    2021-10-12T09:33:00+00:00

    Answer:

    (0,2) & (3,0)

    Step-by-step explanation:

    Given the equation 2x+3y=6:

    Step 1:

    To find the y-intercept, you want to set the x value to zero. This will allow you to solve for y, and find where the equation intercepts why on the 0 line:

    2(0)+3y=6 \\ 0+3y=6\\ 3y=6\\ y=\frac{6}{3} \\  y = 2

    So, at x=0, y=2. or (0,2)

    Step 2:

    Set y = 0 and solve for x:

    2x+3(0)=6\\ 2x+0=6\\ 2x=6\\ x=\frac{6}{2}\\  x=3

    so at y=0, x=3. which is the same as saying: when x=3, y=0, or (3,0)

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