What are the zeros of the quadratic function f(x) = 6×2 + 12x – 7?

Question

What are the zeros of the quadratic function f(x) = 6×2 + 12x – 7?

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Kennedy 2 days 2021-10-11T00:21:11+00:00 2 Answers 0

Answers ( )

    0
    2021-10-11T00:22:37+00:00

    Answer:

    -6 ± √78\6 [0.47196014…, -2.47196014… = x]

    Step-by-step explanation:

    The roots [zeros] are the x-values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

    0
    2021-10-11T00:22:38+00:00

    Answer:

    x = 1 + √74/6 or x = 1 – √74/6

    Step-by-step explanation:

    Points to remember

    Zeros of a quadratic equation ax² + bx + c = 0

    x = [-b ± √(b² – 4ac)]/2a

    To find the zeros of given quadratic equation

    It is given that,

    6x² +12x – 7 = 0

    Here a = 6, b = -12 and c = -7

    x = [-b ± √(b² – 4ac)]/2a

     =  [-12 ± √(12² – 4*6*(-7))]/2*6

     = [12 ± √(144 +168 )]/12

     =  [12 ± √312]/12

     = [12 ± 2√74]/12

     = 1 ± √74/6

    x = 1 + √74/6 and x = 1 – √74/6

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