What is the binomial expansion of (2x – 3)^5? A) (2x)^ 5 – 15(2x)^ 4 + 90(2x)^ 3 – 270(2x)^ 2 + 405(2x) – 243

Question

What is the binomial expansion of (2x – 3)^5?

A) (2x)^ 5 – 15(2x)^ 4 + 90(2x)^ 3 – 270(2x)^ 2 + 405(2x) – 243

B) (2x)^ 5 + 15(2x)^ 4 – 90(2x)^ 3 + 270(2x)^ 2 – 405(2x) + 243

C) (2x)^ 5 + 15(2x)^ 4 + 90(2x)^ 3 + 270(2x)^ 2 + 405(2x) + 243

D) 2(x)^ 5 – 30(x)^ 4 + 180(x)^ 3 – 540(2x)^ 2 + 810(x) – 243

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Josie 3 days 2021-10-10T19:14:14+00:00 2 Answers 0

Answers ( )

    0
    2021-10-10T19:15:47+00:00

    Answer:

    the answer is C

    Step-by-step explanation:

    0
    2021-10-10T19:15:51+00:00

    Answer:

    C

    Step-by-step explanation:

    (2x + 3)^5 = C(5,0)2x^5*3^0 +

    C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5

    Recall that

    C(n,r) = n! / (n-r)! r!

    C(5,0) = 1

    C(5,1) = 5

    C(5,2) = 10

    C(5,3) = 10

    C(5,4) = 5

    C(5,5) = 1

    = 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5

    = 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243

    = 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243

    = 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243

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27:3+15-4x7+3-1=? ( )