what is the vertix of the function f(x)=3(x-2)^2+4​

Question

what is the vertix of the function f(x)=3(x-2)^2+4​

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Gabriella 1 week 2021-11-25T11:56:45+00:00 2 Answers 0

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    0
    2021-11-25T11:58:05+00:00

    Answer:

    (2,4)

    Step-by-step explanation:

    the function is in the vertex form which is a(x – h)² + k, where (h,k) is the vertex of a function

    we have the function f(x) = 3(x – 2)² + 4. lets list what each value is:

    a = 3

    h = 2

    k = 4

    the vertex is (h,k), meaning the vertex is (2,4)

    0
    2021-11-25T11:58:16+00:00

    Answer:

    (2, 4)

    Step-by-step explanation:

    Compare the given function

    f(x)=3(x-2)^2+4​ to the general vertex form of the equation of a parabola:

    f(x) = a(x-h)^2 + k, where (h, k) represents the vertex.

    Thus, h = 2 and k = 4.

    The vertex is at (2, 4).

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