## Which is true given the two equations below? 3 + 2 = 5 3 – 2 = 1 A. (3, 2) is the intersection point of t

Question

Which is true given the two equations below?

3 + 2 = 5
3 – 2 = 1
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x – 2y = 1.

B.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x – y = 1.

C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x – 2y = 1.

D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x – y = 1.

in progress 0
2 weeks 2021-09-12T05:16:42+00:00 1 Answer 0

## Answers ( )

(3,2) is the intersection point of the graph of

x + y = 5 and

x – y = 1.

Step-by-step explanation:

The given two equations are as follows:

3 + 2 = 5 …….. (1) and

3 – 2 = 1 ………. (2)

Now, we have to choose the true one from the given options.

I think option B gives the true statement regarding the two equations given above.

It states that (3,2) is the intersection point of the graph of

x + y = 5 and

x – y = 1.

This is because if we put x = 3 and y = 2 in the above equations, then they will give equations (1) and (2). (Answer)