Which is true given the two equations below? 3 + 2 = 5 3 – 2 = 1 A. (3, 2) is the intersection point of t

Question

Which is true given the two equations below?

3 + 2 = 5
3 – 2 = 1
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x – 2y = 1.

B.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x – y = 1.

C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x – 2y = 1.

D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x – y = 1.

in progress 0
Kinsley 2 weeks 2021-09-12T05:16:42+00:00 1 Answer 0

Answers ( )

    0
    2021-09-12T05:18:06+00:00

    Answer:

    (3,2) is the intersection point of the graph of

    x + y = 5 and

    x – y = 1.

    Step-by-step explanation:

    The given two equations are as follows:

    3 + 2 = 5 …….. (1) and  

    3 – 2 = 1 ………. (2)

    Now, we have to choose the true one from the given options.

    I think option B gives the true statement regarding the two equations given above.

    It states that (3,2) is the intersection point of the graph of  

    x + y = 5 and  

    x – y = 1.  

    This is because if we put x = 3 and y = 2 in the above equations, then they will give equations (1) and (2). (Answer)

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