Which points are a distance of 5 units from (2, 3) if ? (7, 3) (–1, –1) (0, 3) (2, 8) (−7, 6)

Question

Which points are a distance of 5 units from (2, 3) if ? (7, 3) (–1, –1) (0, 3) (2, 8) (−7, 6)

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Iris 6 days 2021-09-14T21:42:55+00:00 2 Answers 0

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    0
    2021-09-14T21:44:46+00:00

    Answer:

    (7, 3), (–1, –1) and (2, 8) are at a distance of  units from (2, 3).

    Step-by-step explanation:

    We know that the formula of distance is given by:

    Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

    So substituting the given points points to check which points are at a distance of 5 units from (2,3).

    1. (2, 3) and (7, 3):

    \sqrt{(7-2)^2+(3-3)^2} =\sqrt{25} = 5

    2. (2, 3) and (–1, –1):

    \sqrt{(-1-2)^2+(-1-3)^2} =\sqrt{25} = 5

    3. (2, 3) and (0, 3):

    \sqrt{(0-2)^2+(3-3)^2} =\sqrt{4} = 2

    4. (2, 3) and (2, 8):

    \sqrt{(2-2)^2+(8-3)^2} =\sqrt{25} = 5

    5. (2, 3) and (-7, 6):

    \sqrt{(-7-2)^2+(6-3)^2} =\sqrt{90} =9.5

    0
    2021-09-14T21:44:52+00:00

    Answer:

    Step-by-step explanation:

    The correct answer are A B and D

    I just took the test

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