Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how m

Question

Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

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Josephine 37 mins 2021-09-15T21:02:23+00:00 1 Answer 0

Answers ( )

    0
    2021-09-15T21:03:52+00:00

    Answer:

    The dinner cost was
    $
    48

    Step-by-step explanation:

    Let the dinner cost was  $
    x

    Will paid  x
    /4

    Micah paid  1/
    4  of remaining
    (
    1

    1
    /4
    )
    x
    =
    3/4
    x

    i.e  

    4
    /16x

    Sue paid  3/4  of remaining
    (
    1

    1
    /4
    )
    x
    =
    3/4x

    i.e  

    9/16
    x

    Sue paid  $
    15  more than Will.  

    ∴  9/16
    x  -1
    /4
    x
    =  5/16x=15

    or

    x=$48

    Will paid  48
    /4
    =
    $
    1
    2, Miah paid  4
    /16.
    48
    =
    $
    12

    ,Sue paid  9/16⋅
    48=
    $
    27  

    The dinner cost was
    $
    48

    .

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