Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how m

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Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

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Amelia 3 days 2021-09-15T19:30:49+00:00 1 Answer 0

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    2021-09-15T19:32:29+00:00

    Answer:

    The dinner costed $48 in total.

    Step-by-step explanation:

    The amount of bill paid by Will = 1/4 of bill

    Amount of bill paid by Micah and Sue  1: 3

    Let us assume the common factor in the ratio  = m

    So, the amount paid by Micah = 1 x (m) = m

    The amount paid by Sue  = 3 x (m)  = 3 m

    Also, amount paid by Sue  = $15 + Amount paid by Will

    So, the amount paid by Will =  amount paid by Sue – $15   = 3 m – $15

    Total Bill  = Bill amount paid by ( Will + Micah + Sue)  

                   =   m + 3 m + 3 m – 15  = 7 m – 15

    Now, As will paid 1/4 of total bill.

    \frac{1}{4} \times (7 m -15)  = 3m -15\\ \implies (7m - 15)  = 12  m - 60\\\implies 45 = 5 m \\\implies  m = 45/5 = 9

    or,  m = 9

    Now, the total bill = 7 m – 15  = 7(9) – 15  =  $48

    Hence, the dinner costed $48 in total.

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