Write the equation in standard form for the circle with center (4,0) passing through 4,(11/2).

Question

Write the equation in standard form for the circle with center (4,0) passing through 4,(11/2).

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Kaylee 17 hours 2021-10-14T02:15:36+00:00 1 Answer 0

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    2021-10-14T02:17:26+00:00

    Answer:

    The standard equation of circle is  (x-4)^2 + (y)^2  = (\frac{11}{2}) ^2

    Step-by-step explanation:

    The given circle has Center  = (4,0)

    Passing through (4,11/2)

    The standard form of the Circle is given as:

    (x-h)^2 + (y-k)^2  = r^2

    Here, (h,k) is the center coordinates and r : radius of the given circle.

    So, here according to the question:

    (h,k) = (4,0)  , (x,y) = (4,11/2)

    Putting the above value sin the equation of circle, determine the value of r:

    (4-4)^2 + (\frac{11}{2} -0)^2  = r^2\\\implies (\frac{11}{2}) ^2 = r^2\\\implies r = (\frac{11}{2})

    Hence, the standard equation of circle is  (x-4)^2 + (y-0)^2  = (\frac{11}{2}) ^2

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