Write the standard form of the equation that is parallel to y = -3x + 3 and goes through point (-5, 5).

Question

Write the standard form of the equation that is parallel to y = -3x + 3 and goes through point (-5, 5).

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Clara 2 weeks 2021-09-12T04:30:50+00:00 1 Answer 0

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    2021-09-12T04:32:17+00:00

    3x + y = -10. The standard form of the equation that is parallel to y = -3x + 3 and goes through point (-5, 5) is 3x + y = -10.

    The equation is written in the slope-intercept form y = mx +b. So:

    y = -3x + 3

    The slope m = -3

    Since the slopes of parallel lines are the same, we are looking for a slope line m = -3 and goes through point (-5, 5).

    With the slope-intercept form:

    y = mx + b

    Introducing the slope m = -3:

    y = -3x + b

    Introducing the point (-5, 5):

    5 = -3(-5) + b

    5 = 15 + b

    b= 5 – 15

    b = -10

    then

    y = -3x -10

    write the equation in standard form ax + by = c:

    y = -3x -10

    3x + y = -10

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