Write the standard form of the equation that is parallel to y = -6x + 5 and goes through point (4, 4).

Question

Write the standard form of the equation that is parallel to y = -6x + 5 and goes through point (4, 4).

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Nevaeh 6 days 2021-09-12T04:26:20+00:00 1 Answer 0

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    2021-09-12T04:27:36+00:00

    6x + y = 28.  The standard form of the equation that is parallel to y = -6x + 5 and goes through point (4, 4) is 6x + y = 28.

    The equation is written in the slope-intercept form y = mx +b. So:

    y = -6x + 5

    The slope m = -6

    Since the slopes of parallel lines are the same, we are looking for a slope line m = -6 and goes through point (4, 4).

    With the slope-intercept form:

    y = mx + b

    Introducing the slope m = -6:

    y = -6x + b

    Introducing the point (4, 4):

    4 = -6(4) + b

    b = 4 + 6(4)

    b= 24 + 4

    b = 28

    Then

    y = -6x + 28

    write the equation in standard form ax + by = c:

    y = -6x + 28

    6x + y = 28

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