You need 320 mL of a 65% alcohol solution. On hand, you have a 60% alcohol mixture. How much of the 60% alcohol mixture and pure alcohol wil

Question

You need 320 mL of a 65% alcohol solution. On hand, you have a 60% alcohol mixture. How much of the 60% alcohol mixture and pure alcohol will you need to obtain the desired solution?

You will need
____ mL of the 60% solution
and
_____ mL of pure alcohol.

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Kennedy 1 week 2021-09-15T01:00:21+00:00 1 Answer 0

Answers ( )

    0
    2021-09-15T01:01:41+00:00

    Answer:

    You will need

    280 mL of the 60% solution

    and  40 mL of pure alcohol.

    Step-by-step explanation:

    Let ‘x’ be the amount of 60% alcohol solution and y the amount of pure alcohol.

    Therefore:

    (0.6x + y)/320 = 0.65 ⇒ 0.6x + y = 208

    x + y = 320

    Solving the sistem of equations:

    x = 280 and y = 40

    Therefore, You will need

    280 mL of the 60% solution

    and  40 mL of pure alcohol.

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